Answer by ixjxk for Overloading a function using templates
I've improved https://stackoverflow.com/a/60271100/12894563 answer. 'If constexpr' can help in this situation:template <typename T>struct always_false : std::false_type {};template <typename...
View ArticleAnswer by ixjxk for Overloading a function using templates
What about this solution? A code with the function will be compiled if the type T is satisfied your requrements. Otherwise, the static assertion failed.#include <type_traits>enum anEnum {...
View ArticleAnswer by NutCracker for Overloading a function using templates
In addition to non-C++20 answer, if you are, by any chance, able to use C++20 and its concepts feature, I would suggest you the following implementation:#include <iostream>#include...
View ArticleAnswer by StoryTeller - Unslander Monica for Overloading a function using...
There are a couple of ways to accomplish this. All involve using the type_traits header. You can static assert on the types in question in the body of the function, for instance.Or, if you need to...
View ArticleOverloading a function using templates
I am trying to define a function using templates and I want the typename to be either int or anEnum (a specific enum I had defined). I have tried the following but I have failed:template <int |...
View Article